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36w^2-64=0
a = 36; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·36·(-64)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*36}=\frac{-96}{72} =-1+1/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*36}=\frac{96}{72} =1+1/3 $
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